(x-5)(x^2+12x+27)=0

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Solution for (x-5)(x^2+12x+27)=0 equation:


Simplifying
(x + -5)(x2 + 12x + 27) = 0

Reorder the terms:
(-5 + x)(x2 + 12x + 27) = 0

Reorder the terms:
(-5 + x)(27 + 12x + x2) = 0

Multiply (-5 + x) * (27 + 12x + x2)
(-5(27 + 12x + x2) + x(27 + 12x + x2)) = 0
((27 * -5 + 12x * -5 + x2 * -5) + x(27 + 12x + x2)) = 0
((-135 + -60x + -5x2) + x(27 + 12x + x2)) = 0
(-135 + -60x + -5x2 + (27 * x + 12x * x + x2 * x)) = 0
(-135 + -60x + -5x2 + (27x + 12x2 + x3)) = 0

Reorder the terms:
(-135 + -60x + 27x + -5x2 + 12x2 + x3) = 0

Combine like terms: -60x + 27x = -33x
(-135 + -33x + -5x2 + 12x2 + x3) = 0

Combine like terms: -5x2 + 12x2 = 7x2
(-135 + -33x + 7x2 + x3) = 0

Solving
-135 + -33x + 7x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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